Solve for x 3-5(x+4)=8(2x-3)

$3 - 5 (x + 4) = 8 (2 x - 3)$

Simplify $3 - 5 (x + 4)$ .

Simplify each term.

Apply the distributive property.

$3 - 5 x - 5 \cdot 4 = 8 (2 x - 3)$

Multiply $- 5$ by $4$ .

$3 - 5 x - 20 = 8 (2 x - 3)$

Subtract $20$ from $3$ .

$- 5 x - 17 = 8 (2 x - 3)$

Simplify $8 (2 x - 3)$ .

Apply the distributive property.

$- 5 x - 17 = 8 (2 x) + 8 \cdot - 3$

Multiply.

Multiply $2$ by $8$ .

$- 5 x - 17 = 16 x + 8 \cdot - 3$

Multiply $8$ by $- 3$ .

$- 5 x - 17 = 16 x - 24$

Move all terms containing $x$ to the left side of the equation.

Subtract $16 x$ from both sides of the equation.

$- 5 x - 17 - 16 x = - 24$

Subtract $16 x$ from $- 5 x$ .

$- 21 x - 17 = - 24$

Move all terms not containing $x$ to the right side of the equation.

Add $17$ to both sides of the equation.

$- 21 x = - 24 + 17$

Add $- 24$ and $17$ .

$- 21 x = - 7$

Divide each term in $- 21 x = - 7$ by $- 21$ and simplify.

Divide each term in $- 21 x = - 7$ by $- 21$ .

$\frac{- 21 x}{- 21} = \frac{- 7}{- 21}$

Simplify the left side.

Cancel the common factor of $- 21$ .

Cancel the common factor.

$\frac{- 21 x}{- 21} = \frac{- 7}{- 21}$

Divide $x$ by $1$ .

$x = \frac{- 7}{- 21}$

Simplify the right side.

Cancel the common factor of $- 7$ and $- 21$ .

Factor $- 7$ out of $- 7$ .

$x = \frac{- 7 (1)}{- 21}$

Cancel the common factors.

Factor $- 7$ out of $- 21$ .

$x = \frac{- 7 \cdot 1}{- 7 \cdot 3}$

Cancel the common factor.

$x = \frac{- 7 \cdot 1}{- 7 \cdot 3}$

Rewrite the expression.

$x = \frac{1}{3}$

The result can be shown in multiple forms.

Exact Form:

$x = \frac{1}{3}$

Decimal Form:

$x = 0.\overline{3}$

Solve for x 3-5(x+4)=8(2x-3)

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