Solve for x -3/5x=18

$- \frac{3}{5} x = 18$

Step 1

Multiply both sides of the equation by $- \frac{5}{3}$ .

$- \frac{5}{3} (- \frac{3}{5} x) = - \frac{5}{3} \cdot 18$

Step 2

Simplify both sides of the equation.

Simplify the left side.

Simplify $- \frac{5}{3} (- \frac{3}{5} x)$ .

Combine $x$ and $\frac{3}{5}$ .

$- \frac{5}{3} (- \frac{x \cdot 3}{5}) = - \frac{5}{3} \cdot 18$

Cancel the common factor of $5$ .

Move the leading negative in $- \frac{5}{3}$ into the numerator.

$\frac{- 5}{3} (- \frac{x \cdot 3}{5}) = - \frac{5}{3} \cdot 18$

Move the leading negative in $- \frac{x \cdot 3}{5}$ into the numerator.

$\frac{- 5}{3} \cdot \frac{- x \cdot 3}{5} = - \frac{5}{3} \cdot 18$

Factor $5$ out of $- 5$ .

$\frac{5 (- 1)}{3} \cdot \frac{- x \cdot 3}{5} = - \frac{5}{3} \cdot 18$

Cancel the common factor.

$\frac{5 \cdot - 1}{3} \cdot \frac{- x \cdot 3}{5} = - \frac{5}{3} \cdot 18$

Rewrite the expression.

$\frac{- 1}{3} (- x \cdot 3) = - \frac{5}{3} \cdot 18$

Cancel the common factor of $3$ .

Factor $3$ out of $- x \cdot 3$ .

$\frac{- 1}{3} (3 \cdot (- x)) = - \frac{5}{3} \cdot 18$

Cancel the common factor.

$\frac{- 1}{3} (3 \cdot (- x)) = - \frac{5}{3} \cdot 18$

Rewrite the expression.

$- - x = - \frac{5}{3} \cdot 18$

Multiply.

Multiply $- 1$ by $- 1$ .

$1 x = - \frac{5}{3} \cdot 18$

Multiply $x$ by $1$ .

$x = - \frac{5}{3} \cdot 18$

Simplify the right side.

Simplify $- \frac{5}{3} \cdot 18$ .

Cancel the common factor of $3$ .

Move the leading negative in $- \frac{5}{3}$ into the numerator.

$x = \frac{- 5}{3} \cdot 18$

Factor $3$ out of $18$ .

$x = \frac{- 5}{3} \cdot (3 (6))$

Cancel the common factor.

$x = \frac{- 5}{3} \cdot (3 \cdot 6)$

Rewrite the expression.

$x = - 5 \cdot 6$

Multiply $- 5$ by $6$ .

$x = - 30$

Solve for x -3/5x=18

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