Solve for x 3(5x-4)=8x+2

$3 (5 x - 4) = 8 x + 2$

Step 1

Simplify $3 (5 x - 4)$ .

Rewrite.

$0 + 0 + 3 (5 x - 4) = 8 x + 2$

Simplify by adding zeros.

$3 (5 x - 4) = 8 x + 2$

Apply the distributive property.

$3 (5 x) + 3 \cdot - 4 = 8 x + 2$

Multiply.

Multiply $5$ by $3$ .

$15 x + 3 \cdot - 4 = 8 x + 2$

Multiply $3$ by $- 4$ .

$15 x - 12 = 8 x + 2$

Step 2

Move all terms containing $x$ to the left side of the equation.

Subtract $8 x$ from both sides of the equation.

$15 x - 12 - 8 x = 2$

Subtract $8 x$ from $15 x$ .

$7 x - 12 = 2$

Step 3

Move all terms not containing $x$ to the right side of the equation.

Add $12$ to both sides of the equation.

$7 x = 2 + 12$

Add $2$ and $12$ .

$7 x = 14$

Step 4

Divide each term in $7 x = 14$ by $7$ and simplify.

Divide each term in $7 x = 14$ by $7$ .

$\frac{7 x}{7} = \frac{14}{7}$

Simplify the left side.

Cancel the common factor of $7$ .

Cancel the common factor.

$\frac{7 x}{7} = \frac{14}{7}$

Divide $x$ by $1$ .

$x = \frac{14}{7}$

Simplify the right side.

Divide $14$ by $7$ .

$x = 2$