Solve for x (36)+(3x)=24

$(3 \cdot 6) + (3 \cdot x) = 24$

Multiply $3$ by $6$ .

$18 + 3 x = 24$

Move all terms not containing $x$ to the right side of the equation.

Subtract $18$ from both sides of the equation.

$3 x = 24 - 18$

Subtract $18$ from $24$ .

$3 x = 6$

Divide each term in $3 x = 6$ by $3$ and simplify.

Divide each term in $3 x = 6$ by $3$ .

$\frac{3 x}{3} = \frac{6}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 x}{3} = \frac{6}{3}$

Divide $x$ by $1$ .

$x = \frac{6}{3}$

Simplify the right side.

Divide $6$ by $3$ .

$x = 2$

Solve for x (3*6)+(3*x)=24