Solve for x 3(6x-5)=3(6x-5)+x

$3 (6 x - 5) = 3 (6 x - 5) + x$

Step 1

Since $x$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$3 (6 x - 5) + x = 3 (6 x - 5)$

Step 2

Simplify $3 (6 x - 5) + x$ .

Simplify each term.

Apply the distributive property.

$3 (6 x) + 3 \cdot - 5 + x = 3 (6 x - 5)$

Multiply $6$ by $3$ .

$18 x + 3 \cdot - 5 + x = 3 (6 x - 5)$

Multiply $3$ by $- 5$ .

$18 x - 15 + x = 3 (6 x - 5)$

Add $18 x$ and $x$ .

$19 x - 15 = 3 (6 x - 5)$

Step 3

Simplify $3 (6 x - 5)$ .

Apply the distributive property.

$19 x - 15 = 3 (6 x) + 3 \cdot - 5$

Multiply.

Multiply $6$ by $3$ .

$19 x - 15 = 18 x + 3 \cdot - 5$

Multiply $3$ by $- 5$ .

$19 x - 15 = 18 x - 15$

Step 4

Move all terms containing $x$ to the left side of the equation.

Subtract $18 x$ from both sides of the equation.

$19 x - 15 - 18 x = - 15$

Subtract $18 x$ from $19 x$ .

$x - 15 = - 15$

Step 5

Move all terms not containing $x$ to the right side of the equation.

Add $15$ to both sides of the equation.

$x = - 15 + 15$

Add $- 15$ and $15$ .

$x = 0$