Solve for x -3/7x=6/35

$- \frac{3}{7} x = \frac{6}{35}$

Step 1

Multiply both sides of the equation by $- \frac{7}{3}$ .

$- \frac{7}{3} (- \frac{3}{7} x) = - \frac{7}{3} \cdot \frac{6}{35}$

Step 2

Simplify both sides of the equation.

Simplify the left side.

Simplify $- \frac{7}{3} (- \frac{3}{7} x)$ .

Combine $x$ and $\frac{3}{7}$ .

$- \frac{7}{3} (- \frac{x \cdot 3}{7}) = - \frac{7}{3} \cdot \frac{6}{35}$

Cancel the common factor of $7$ .

Move the leading negative in $- \frac{7}{3}$ into the numerator.

$\frac{- 7}{3} (- \frac{x \cdot 3}{7}) = - \frac{7}{3} \cdot \frac{6}{35}$

Move the leading negative in $- \frac{x \cdot 3}{7}$ into the numerator.

$\frac{- 7}{3} \cdot \frac{- x \cdot 3}{7} = - \frac{7}{3} \cdot \frac{6}{35}$

Factor $7$ out of $- 7$ .

$\frac{7 (- 1)}{3} \cdot \frac{- x \cdot 3}{7} = - \frac{7}{3} \cdot \frac{6}{35}$

Cancel the common factor.

$\frac{7 \cdot - 1}{3} \cdot \frac{- x \cdot 3}{7} = - \frac{7}{3} \cdot \frac{6}{35}$

Rewrite the expression.

$\frac{- 1}{3} (- x \cdot 3) = - \frac{7}{3} \cdot \frac{6}{35}$

Cancel the common factor of $3$ .

Factor $3$ out of $- x \cdot 3$ .

$\frac{- 1}{3} (3 \cdot (- x)) = - \frac{7}{3} \cdot \frac{6}{35}$

Cancel the common factor.

$\frac{- 1}{3} (3 \cdot (- x)) = - \frac{7}{3} \cdot \frac{6}{35}$

Rewrite the expression.

$- - x = - \frac{7}{3} \cdot \frac{6}{35}$

Multiply.

Multiply $- 1$ by $- 1$ .

$1 x = - \frac{7}{3} \cdot \frac{6}{35}$

Multiply $x$ by $1$ .

$x = - \frac{7}{3} \cdot \frac{6}{35}$

Simplify the right side.

Simplify $- \frac{7}{3} \cdot \frac{6}{35}$ .

Cancel the common factor of $7$ .

Move the leading negative in $- \frac{7}{3}$ into the numerator.

$x = \frac{- 7}{3} \cdot \frac{6}{35}$

Factor $7$ out of $- 7$ .

$x = \frac{7 (- 1)}{3} \cdot \frac{6}{35}$

Factor $7$ out of $35$ .

$x = \frac{7 \cdot - 1}{3} \cdot \frac{6}{7 \cdot 5}$

Cancel the common factor.

$x = \frac{7 \cdot - 1}{3} \cdot \frac{6}{7 \cdot 5}$

Rewrite the expression.

$x = \frac{- 1}{3} \cdot \frac{6}{5}$

Cancel the common factor of $3$ .

Factor $3$ out of $6$ .

$x = \frac{- 1}{3} \cdot \frac{3 (2)}{5}$

Cancel the common factor.

$x = \frac{- 1}{3} \cdot \frac{3 \cdot 2}{5}$

Rewrite the expression.

$x = - \frac{2}{5}$

Step 3

The result can be shown in multiple forms.

Exact Form:

$x = - \frac{2}{5}$

Decimal Form:

$x = - 0.4$

Solve for x -3/7x=6/35

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