Solve for x -3/8x=15

$- \frac{3}{8} x = 15$

Step 1

Multiply both sides of the equation by $- \frac{8}{3}$ .

$- \frac{8}{3} (- \frac{3}{8} x) = - \frac{8}{3} \cdot 15$

Step 2

Simplify both sides of the equation.

Simplify the left side.

Simplify $- \frac{8}{3} (- \frac{3}{8} x)$ .

Combine $x$ and $\frac{3}{8}$ .

$- \frac{8}{3} (- \frac{x \cdot 3}{8}) = - \frac{8}{3} \cdot 15$

Cancel the common factor of $8$ .

Move the leading negative in $- \frac{8}{3}$ into the numerator.

$\frac{- 8}{3} (- \frac{x \cdot 3}{8}) = - \frac{8}{3} \cdot 15$

Move the leading negative in $- \frac{x \cdot 3}{8}$ into the numerator.

$\frac{- 8}{3} \cdot \frac{- x \cdot 3}{8} = - \frac{8}{3} \cdot 15$

Factor $8$ out of $- 8$ .

$\frac{8 (- 1)}{3} \cdot \frac{- x \cdot 3}{8} = - \frac{8}{3} \cdot 15$

Cancel the common factor.

$\frac{8 \cdot - 1}{3} \cdot \frac{- x \cdot 3}{8} = - \frac{8}{3} \cdot 15$

Rewrite the expression.

$\frac{- 1}{3} (- x \cdot 3) = - \frac{8}{3} \cdot 15$

Cancel the common factor of $3$ .

Factor $3$ out of $- x \cdot 3$ .

$\frac{- 1}{3} (3 \cdot (- x)) = - \frac{8}{3} \cdot 15$

Cancel the common factor.

$\frac{- 1}{3} (3 \cdot (- x)) = - \frac{8}{3} \cdot 15$

Rewrite the expression.

$- - x = - \frac{8}{3} \cdot 15$

Multiply.

Multiply $- 1$ by $- 1$ .

$1 x = - \frac{8}{3} \cdot 15$

Multiply $x$ by $1$ .

$x = - \frac{8}{3} \cdot 15$

Simplify the right side.

Simplify $- \frac{8}{3} \cdot 15$ .

Cancel the common factor of $3$ .

Move the leading negative in $- \frac{8}{3}$ into the numerator.

$x = \frac{- 8}{3} \cdot 15$

Factor $3$ out of $15$ .

$x = \frac{- 8}{3} \cdot (3 (5))$

Cancel the common factor.

$x = \frac{- 8}{3} \cdot (3 \cdot 5)$

Rewrite the expression.

$x = - 8 \cdot 5$

Multiply $- 8$ by $5$ .

$x = - 40$

Solve for x -3/8x=15

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