Solve for x 3 log of x-4=6

$3 \log (x - 4) = 6$

Divide each term in $3 \log (x - 4) = 6$ by $3$ and simplify.

Divide each term in $3 \log (x - 4) = 6$ by $3$ .

$\frac{3 \log (x - 4)}{3} = \frac{6}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 \log (x - 4)}{3} = \frac{6}{3}$

Divide $\log (x - 4)$ by $1$ .

$\log (x - 4) = \frac{6}{3}$

Simplify the right side.

Divide $6$ by $3$ .

$\log (x - 4) = 2$

Rewrite $\log (x - 4) = 2$ in exponential form using the definition of a logarithm. If $x$ and $b$ are positive real numbers and $b \neq 1$ , then $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ .

$10^{2} = x - 4$

Solve for $x$ .

Rewrite the equation as $x - 4 = 10^{2}$ .

$x - 4 = 10^{2}$

Raise $10$ to the power of $2$ .

$x - 4 = 100$

Move all terms not containing $x$ to the right side of the equation.

Add $4$ to both sides of the equation.

$x = 100 + 4$

Add $100$ and $4$ .

$x = 104$

Solve for x 3 log of x-4=6

Related Questions

Support LCMGCF.com by disabling your adblocker.