Solve for x 3(x+1)+2<11

$3 (x + 1) + 2 < 11$

Step 1

Simplify $3 (x + 1) + 2$ .

Simplify each term.

Apply the distributive property.

$3 x + 3 \cdot 1 + 2 < 11$

Multiply $3$ by $1$ .

$3 x + 3 + 2 < 11$

Add $3$ and $2$ .

$3 x + 5 < 11$

Step 2

Move all terms not containing $x$ to the right side of the inequality.

Subtract $5$ from both sides of the inequality.

$3 x < 11 - 5$

Subtract $5$ from $11$ .

$3 x < 6$

Step 3

Divide each term in $3 x < 6$ by $3$ and simplify.

Divide each term in $3 x < 6$ by $3$ .

$\frac{3 x}{3} < \frac{6}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 x}{3} < \frac{6}{3}$

Divide $x$ by $1$ .

$x < \frac{6}{3}$

Simplify the right side.

Divide $6$ by $3$ .

$x < 2$

Step 4

The result can be shown in multiple forms.

Inequality Form:

$x < 2$

Interval Notation:

$(- \infty, 2)$