Solve for x 3(x-1)=2(x+3)

$3 (x - 1) = 2 (x + 3)$

Step 1

Simplify $3 (x - 1)$ .

Rewrite.

$0 + 0 + 3 (x - 1) = 2 (x + 3)$

Simplify by adding zeros.

$3 (x - 1) = 2 (x + 3)$

Apply the distributive property.

$3 x + 3 \cdot - 1 = 2 (x + 3)$

Multiply $3$ by $- 1$ .

$3 x - 3 = 2 (x + 3)$

Step 2

Simplify $2 (x + 3)$ .

Apply the distributive property.

$3 x - 3 = 2 x + 2 \cdot 3$

Multiply $2$ by $3$ .

$3 x - 3 = 2 x + 6$

Step 3

Move all terms containing $x$ to the left side of the equation.

Subtract $2 x$ from both sides of the equation.

$3 x - 3 - 2 x = 6$

Subtract $2 x$ from $3 x$ .

$x - 3 = 6$

Step 4

Move all terms not containing $x$ to the right side of the equation.

Add $3$ to both sides of the equation.

$x = 6 + 3$

Add $6$ and $3$ .

$x = 9$