Solve for x 3^(x+1)<=27

$3^{x + 1} \leq 27$

Step 1

Create equivalent expressions in the equation that all have equal bases.

$3^{x + 1} \leq 3^{3}$

Step 2

Since the bases are the same, then two expressions are only equal if the exponents are also equal.

$x + 1 \leq 3$

Step 3

Move all terms not containing $x$ to the right side of the inequality.

Subtract $1$ from both sides of the inequality.

$x \leq 3 - 1$

Subtract $1$ from $3$ .

$x \leq 2$

Step 4

The result can be shown in multiple forms.

Inequality Form:

$x \leq 2$

Interval Notation:

$(- \infty, 2]$

Step 5