Solve for x 3^(x+1)=27

$3^{x + 1} = 27$

Step 1

Create equivalent expressions in the equation that all have equal bases.

$3^{x + 1} = 3^{3}$

Step 2

Since the bases are the same, then two expressions are only equal if the exponents are also equal.

$x + 1 = 3$

Step 3

Move all terms not containing $x$ to the right side of the equation.

Subtract $1$ from both sides of the equation.

$x = 3 - 1$

Subtract $1$ from $3$ .

$x = 2$