Solve for x 3(x-1)=2x-3+3x

$3 (x - 1) = 2 x - 3 + 3 x$

Since $x$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$2 x - 3 + 3 x = 3 (x - 1)$

Add $2 x$ and $3 x$ .

$5 x - 3 = 3 (x - 1)$

Simplify $3 (x - 1)$ .

Apply the distributive property.

$5 x - 3 = 3 x + 3 \cdot - 1$

Multiply $3$ by $- 1$ .

$5 x - 3 = 3 x - 3$

Move all terms containing $x$ to the left side of the equation.

Subtract $3 x$ from both sides of the equation.

$5 x - 3 - 3 x = - 3$

Subtract $3 x$ from $5 x$ .

$2 x - 3 = - 3$

Move all terms not containing $x$ to the right side of the equation.

Add $3$ to both sides of the equation.

$2 x = - 3 + 3$

Add $- 3$ and $3$ .

$2 x = 0$

Divide each term in $2 x = 0$ by $2$ and simplify.

Divide each term in $2 x = 0$ by $2$ .

$\frac{2 x}{2} = \frac{0}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{0}{2}$

Divide $x$ by $1$ .

$x = \frac{0}{2}$

Simplify the right side.

Divide $0$ by $2$ .

$x = 0$