Solve for x 3(x-1)+5=6-(x+2)

$3 (x - 1) + 5 = 6 - (x + 2)$

Simplify $3 (x - 1) + 5$ .

Simplify each term.

Apply the distributive property.

$3 x + 3 \cdot - 1 + 5 = 6 - (x + 2)$

Multiply $3$ by $- 1$ .

$3 x - 3 + 5 = 6 - (x + 2)$

Add $- 3$ and $5$ .

$3 x + 2 = 6 - (x + 2)$

Simplify $6 - (x + 2)$ .

Simplify each term.

Apply the distributive property.

$3 x + 2 = 6 - x - 1 \cdot 2$

Multiply $- 1$ by $2$ .

$3 x + 2 = 6 - x - 2$

Subtract $2$ from $6$ .

$3 x + 2 = - x + 4$

Move all terms containing $x$ to the left side of the equation.

Add $x$ to both sides of the equation.

$3 x + 2 + x = 4$

Add $3 x$ and $x$ .

$4 x + 2 = 4$

Move all terms not containing $x$ to the right side of the equation.

Subtract $2$ from both sides of the equation.

$4 x = 4 - 2$

Subtract $2$ from $4$ .

$4 x = 2$

Divide each term in $4 x = 2$ by $4$ and simplify.

Divide each term in $4 x = 2$ by $4$ .

$\frac{4 x}{4} = \frac{2}{4}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 x}{4} = \frac{2}{4}$

Divide $x$ by $1$ .

$x = \frac{2}{4}$

Simplify the right side.

Cancel the common factor of $2$ and $4$ .

Factor $2$ out of $2$ .

$x = \frac{2 (1)}{4}$

Cancel the common factors.

Factor $2$ out of $4$ .

$x = \frac{2 \cdot 1}{2 \cdot 2}$

Cancel the common factor.

$x = \frac{2 \cdot 1}{2 \cdot 2}$

Rewrite the expression.

$x = \frac{1}{2}$

The result can be shown in multiple forms.

Exact Form:

$x = \frac{1}{2}$

Decimal Form:

$x = 0.5$

Solve for x 3(x-1)+5=6-(x+2)

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