Solve for x 3(x-2)-1=2(x-5(x+4))

$3 (x - 2) - 1 = 2 (x - 5 (x + 4))$

Since $x$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$2 (x - 5 (x + 4)) = 3 (x - 2) - 1$

Simplify $2 (x - 5 (x + 4))$ .

Rewrite.

$0 + 0 + 2 (x - 5 (x + 4)) = 3 (x - 2) - 1$

Simplify by adding zeros.

$2 (x - 5 (x + 4)) = 3 (x - 2) - 1$

Simplify each term.

Apply the distributive property.

$2 (x - 5 x - 5 \cdot 4) = 3 (x - 2) - 1$

Multiply $- 5$ by $4$ .

$2 (x - 5 x - 20) = 3 (x - 2) - 1$

Simplify terms.

Subtract $5 x$ from $x$ .

$2 (- 4 x - 20) = 3 (x - 2) - 1$

Apply the distributive property.

$2 (- 4 x) + 2 \cdot - 20 = 3 (x - 2) - 1$

Multiply.

Multiply $- 4$ by $2$ .

$- 8 x + 2 \cdot - 20 = 3 (x - 2) - 1$

Multiply $2$ by $- 20$ .

$- 8 x - 40 = 3 (x - 2) - 1$

Simplify $3 (x - 2) - 1$ .

Simplify each term.

Apply the distributive property.

$- 8 x - 40 = 3 x + 3 \cdot - 2 - 1$

Multiply $3$ by $- 2$ .

$- 8 x - 40 = 3 x - 6 - 1$

Subtract $1$ from $- 6$ .

$- 8 x - 40 = 3 x - 7$

Move all terms containing $x$ to the left side of the equation.

Subtract $3 x$ from both sides of the equation.

$- 8 x - 40 - 3 x = - 7$

Subtract $3 x$ from $- 8 x$ .

$- 11 x - 40 = - 7$

Move all terms not containing $x$ to the right side of the equation.

Add $40$ to both sides of the equation.

$- 11 x = - 7 + 40$

Add $- 7$ and $40$ .

$- 11 x = 33$

Divide each term in $- 11 x = 33$ by $- 11$ and simplify.

Divide each term in $- 11 x = 33$ by $- 11$ .

$\frac{- 11 x}{- 11} = \frac{33}{- 11}$

Simplify the left side.

Cancel the common factor of $- 11$ .

Cancel the common factor.

$\frac{- 11 x}{- 11} = \frac{33}{- 11}$

Divide $x$ by $1$ .

$x = \frac{33}{- 11}$

Simplify the right side.

Divide $33$ by $- 11$ .

$x = - 3$

Solve for x 3(x-2)-1=2(x-5(x+4))

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