Solve for x 3^(x+2)>=27

$3^{x + 2} \geq 27$

Create equivalent expressions in the equation that all have equal bases.

$3^{x + 2} \geq 3^{3}$

Since the bases are the same, then two expressions are only equal if the exponents are also equal.

$x + 2 \geq 3$

Move all terms not containing $x$ to the right side of the inequality.

Subtract $2$ from both sides of the inequality.

$x \geq 3 - 2$

Subtract $2$ from $3$ .

$x \geq 1$

The result can be shown in multiple forms.

Inequality Form:

$x \geq 1$

Interval Notation:

$[1, \infty)$