Solve for x 3(x+2)=-5-2(x-3)

$3 (x + 2) = - 5 - 2 (x - 3)$

Simplify $3 (x + 2)$ .

Rewrite.

$0 + 0 + 3 (x + 2) = - 5 - 2 (x - 3)$

Simplify by adding zeros.

$3 (x + 2) = - 5 - 2 (x - 3)$

Apply the distributive property.

$3 x + 3 \cdot 2 = - 5 - 2 (x - 3)$

Multiply $3$ by $2$ .

$3 x + 6 = - 5 - 2 (x - 3)$

Simplify $- 5 - 2 (x - 3)$ .

Simplify each term.

Apply the distributive property.

$3 x + 6 = - 5 - 2 x - 2 \cdot - 3$

Multiply $- 2$ by $- 3$ .

$3 x + 6 = - 5 - 2 x + 6$

Add $- 5$ and $6$ .

$3 x + 6 = - 2 x + 1$

Move all terms containing $x$ to the left side of the equation.

Add $2 x$ to both sides of the equation.

$3 x + 6 + 2 x = 1$

Add $3 x$ and $2 x$ .

$5 x + 6 = 1$

Move all terms not containing $x$ to the right side of the equation.

Subtract $6$ from both sides of the equation.

$5 x = 1 - 6$

Subtract $6$ from $1$ .

$5 x = - 5$

Divide each term in $5 x = - 5$ by $5$ and simplify.

Divide each term in $5 x = - 5$ by $5$ .

$\frac{5 x}{5} = \frac{- 5}{5}$

Simplify the left side.

Cancel the common factor of $5$ .

Cancel the common factor.

$\frac{5 x}{5} = \frac{- 5}{5}$

Divide $x$ by $1$ .

$x = \frac{- 5}{5}$

Simplify the right side.

Divide $- 5$ by $5$ .

$x = - 1$