Solve for x 3(x-2)+7=8-(4x+7)

$3 (x - 2) + 7 = 8 - (4 x + 7)$

Simplify $3 (x - 2) + 7$ .

Simplify each term.

Apply the distributive property.

$3 x + 3 \cdot - 2 + 7 = 8 - (4 x + 7)$

Multiply $3$ by $- 2$ .

$3 x - 6 + 7 = 8 - (4 x + 7)$

Add $- 6$ and $7$ .

$3 x + 1 = 8 - (4 x + 7)$

Simplify $8 - (4 x + 7)$ .

Simplify each term.

Apply the distributive property.

$3 x + 1 = 8 - (4 x) - 1 \cdot 7$

Multiply $4$ by $- 1$ .

$3 x + 1 = 8 - 4 x - 1 \cdot 7$

Multiply $- 1$ by $7$ .

$3 x + 1 = 8 - 4 x - 7$

Subtract $7$ from $8$ .

$3 x + 1 = - 4 x + 1$

Move all terms containing $x$ to the left side of the equation.

Add $4 x$ to both sides of the equation.

$3 x + 1 + 4 x = 1$

Add $3 x$ and $4 x$ .

$7 x + 1 = 1$

Move all terms not containing $x$ to the right side of the equation.

Subtract $1$ from both sides of the equation.

$7 x = 1 - 1$

Subtract $1$ from $1$ .

$7 x = 0$

Divide each term in $7 x = 0$ by $7$ and simplify.

Divide each term in $7 x = 0$ by $7$ .

$\frac{7 x}{7} = \frac{0}{7}$

Simplify the left side.

Cancel the common factor of $7$ .

Cancel the common factor.

$\frac{7 x}{7} = \frac{0}{7}$

Divide $x$ by $1$ .

$x = \frac{0}{7}$

Simplify the right side.

Divide $0$ by $7$ .

$x = 0$