Solve for x 3(x+2)+x=2x+16

$3 (x + 2) + x = 2 x + 16$

Simplify $3 (x + 2) + x$ .

Simplify each term.

Apply the distributive property.

$3 x + 3 \cdot 2 + x = 2 x + 16$

Multiply $3$ by $2$ .

$3 x + 6 + x = 2 x + 16$

Add $3 x$ and $x$ .

$4 x + 6 = 2 x + 16$

Move all terms containing $x$ to the left side of the equation.

Subtract $2 x$ from both sides of the equation.

$4 x + 6 - 2 x = 16$

Subtract $2 x$ from $4 x$ .

$2 x + 6 = 16$

Move all terms not containing $x$ to the right side of the equation.

Subtract $6$ from both sides of the equation.

$2 x = 16 - 6$

Subtract $6$ from $16$ .

$2 x = 10$

Divide each term in $2 x = 10$ by $2$ and simplify.

Divide each term in $2 x = 10$ by $2$ .

$\frac{2 x}{2} = \frac{10}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{10}{2}$

Divide $x$ by $1$ .

$x = \frac{10}{2}$

Simplify the right side.

Divide $10$ by $2$ .

$x = 5$