Solve for x -3(x+3)=-3(x+1)-5

$- 3 (x + 3) = - 3 (x + 1) - 5$

Step 1

Simplify $- 3 (x + 3)$ .

Rewrite.

$0 + 0 - 3 (x + 3) = - 3 (x + 1) - 5$

Simplify by adding zeros.

$- 3 (x + 3) = - 3 (x + 1) - 5$

Apply the distributive property.

$- 3 x - 3 \cdot 3 = - 3 (x + 1) - 5$

Multiply $- 3$ by $3$ .

$- 3 x - 9 = - 3 (x + 1) - 5$

Step 2

Simplify $- 3 (x + 1) - 5$ .

Simplify each term.

Apply the distributive property.

$- 3 x - 9 = - 3 x - 3 \cdot 1 - 5$

Multiply $- 3$ by $1$ .

$- 3 x - 9 = - 3 x - 3 - 5$

Subtract $5$ from $- 3$ .

$- 3 x - 9 = - 3 x - 8$

Step 3

Move all terms containing $x$ to the left side of the equation.

Add $3 x$ to both sides of the equation.

$- 3 x - 9 + 3 x = - 8$

Combine the opposite terms in $- 3 x - 9 + 3 x$ .

Add $- 3 x$ and $3 x$ .

$0 - 9 = - 8$

Subtract $9$ from $0$ .

$- 9 = - 8$

Step 4

Since $- 9 \neq - 8$ , there are no solutions.

No solution