Solve for x 3^x+3^(x+1)=36

$3^{x} + 3^{x + 1} = 36$

Factor out $3^{x}$ from the expression.

$3^{x} (1 + 3)$

Add $1$ and $3$ .

$3^{x} \cdot 4 = 36$

Move $4$ to the left of $3^{x}$ .

$4 \cdot 3^{x} = 36$

Divide each term in $(4 \cdot 3^{x}) = 36$ by $4$ and simplify.

Divide each term in $(4 \cdot 3^{x}) = 36$ by $4$ .

$\frac{(4 \cdot 3^{x})}{4} = \frac{36}{4}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 \cdot 3^{x}}{4} = \frac{36}{4}$

Divide $3^{x}$ by $1$ .

$3^{x} = \frac{36}{4}$

Simplify the right side.

Divide $36$ by $4$ .

$3^{x} = 9$

Create equivalent expressions in the equation that all have equal bases.

$3^{x} = 3^{2}$

Since the bases are the same, then two expressions are only equal if the exponents are also equal.

$x = 2$