Solve for x 3-|x+4|=10

$3 - | x + 4 | = 10$

Move all terms not containing $| x + 4 |$ to the right side of the equation.

Subtract $3$ from both sides of the equation.

$- | x + 4 | = 10 - 3$

Subtract $3$ from $10$ .

$- | x + 4 | = 7$

Divide each term in $- | x + 4 | = 7$ by $- 1$ and simplify.

Divide each term in $- | x + 4 | = 7$ by $- 1$ .

$\frac{- | x + 4 |}{- 1} = \frac{7}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{| x + 4 |}{1} = \frac{7}{- 1}$

Divide $| x + 4 |$ by $1$ .

$| x + 4 | = \frac{7}{- 1}$

Simplify the right side.

Divide $7$ by $- 1$ .

$| x + 4 | = - 7$

There is no value of $x$ that makes the equation be true since an absolute value can never be negative.

No solution