Solve for x 3(x+4)=3x

$3 (x + 4) = 3 x$

Step 1

Simplify $3 (x + 4)$ .

Rewrite.

$0 + 0 + 3 (x + 4) = 3 x$

Simplify by adding zeros.

$3 (x + 4) = 3 x$

Apply the distributive property.

$3 x + 3 \cdot 4 = 3 x$

Multiply $3$ by $4$ .

$3 x + 12 = 3 x$

Step 2

Move all terms containing $x$ to the left side of the equation.

Subtract $3 x$ from both sides of the equation.

$3 x + 12 - 3 x = 0$

Combine the opposite terms in $3 x + 12 - 3 x$ .

Subtract $3 x$ from $3 x$ .

$0 + 12 = 0$

Add $0$ and $12$ .

$12 = 0$

Step 3

Since $12 \neq 0$ , there are no solutions.

No solution