Solve for x 3-x+4/7=5

$3 - x + \frac{4}{7} = 5$

Simplify $3 - x + \frac{4}{7}$ .

To write $3$ as a fraction with a common denominator, multiply by $\frac{7}{7}$ .

$- x + 3 \cdot \frac{7}{7} + \frac{4}{7} = 5$

Combine $3$ and $\frac{7}{7}$ .

$- x + \frac{3 \cdot 7}{7} + \frac{4}{7} = 5$

Combine the numerators over the common denominator.

$- x + \frac{3 \cdot 7 + 4}{7} = 5$

Simplify the numerator.

Multiply $3$ by $7$ .

$- x + \frac{21 + 4}{7} = 5$

Add $21$ and $4$ .

$- x + \frac{25}{7} = 5$

Move all terms not containing $x$ to the right side of the equation.

Subtract $\frac{25}{7}$ from both sides of the equation.

$- x = 5 - \frac{25}{7}$

To write $5$ as a fraction with a common denominator, multiply by $\frac{7}{7}$ .

$- x = 5 \cdot \frac{7}{7} - \frac{25}{7}$

Combine $5$ and $\frac{7}{7}$ .

$- x = \frac{5 \cdot 7}{7} - \frac{25}{7}$

Combine the numerators over the common denominator.

$- x = \frac{5 \cdot 7 - 25}{7}$

Simplify the numerator.

Multiply $5$ by $7$ .

$- x = \frac{35 - 25}{7}$

Subtract $25$ from $35$ .

$- x = \frac{10}{7}$

Divide each term in $- x = \frac{10}{7}$ by $- 1$ and simplify.

Divide each term in $- x = \frac{10}{7}$ by $- 1$ .

$\frac{- x}{- 1} = \frac{\frac{10}{7}}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{x}{1} = \frac{\frac{10}{7}}{- 1}$

Divide $x$ by $1$ .

$x = \frac{\frac{10}{7}}{- 1}$

Simplify the right side.

Move the negative one from the denominator of $\frac{\frac{10}{7}}{- 1}$ .

$x = - 1 \cdot \frac{10}{7}$

Rewrite $- 1 \cdot \frac{10}{7}$ as $- \frac{10}{7}$ .

$x = - \frac{10}{7}$

The result can be shown in multiple forms.

Exact Form:

$x = - \frac{10}{7}$

Decimal Form:

$x = - 1.\overline{428571}$

Mixed Number Form:

$x = - 1 \frac{3}{7}$

Solve for x 3-x+4/7=5

Related Questions

Support LCMGCF.com by disabling your adblocker.