Solve for x 3(x-5)=12+2x

$3 (x - 5) = 12 + 2 x$

Simplify $3 (x - 5)$ .

Rewrite.

$0 + 0 + 3 (x - 5) = 12 + 2 x$

Simplify by adding zeros.

$3 (x - 5) = 12 + 2 x$

Apply the distributive property.

$3 x + 3 \cdot - 5 = 12 + 2 x$

Multiply $3$ by $- 5$ .

$3 x - 15 = 12 + 2 x$

Move all terms containing $x$ to the left side of the equation.

Subtract $2 x$ from both sides of the equation.

$3 x - 15 - 2 x = 12$

Subtract $2 x$ from $3 x$ .

$x - 15 = 12$

Move all terms not containing $x$ to the right side of the equation.

Add $15$ to both sides of the equation.

$x = 12 + 15$

Add $12$ and $15$ .

$x = 27$