Solve for x -3(x+8)=X-4

$- 3 (x + 8) = X - 4$

Step 1

Divide each term in $- 3 (x + 8) = X - 4$ by $- 3$ and simplify.

Divide each term in $- 3 (x + 8) = X - 4$ by $- 3$ .

$\frac{- 3 (x + 8)}{- 3} = \frac{X}{- 3} + \frac{- 4}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 (x + 8)}{- 3} = \frac{X}{- 3} + \frac{- 4}{- 3}$

Divide $x + 8$ by $1$ .

$x + 8 = \frac{X}{- 3} + \frac{- 4}{- 3}$

Simplify the right side.

Simplify each term.

Move the negative in front of the fraction.

$x + 8 = - \frac{X}{3} + \frac{- 4}{- 3}$

Dividing two negative values results in a positive value.

$x + 8 = - \frac{X}{3} + \frac{4}{3}$

Step 2

Move all terms not containing $x$ to the right side of the equation.

Subtract $8$ from both sides of the equation.

$x = - \frac{X}{3} + \frac{4}{3} - 8$

To write $- 8$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$x = - \frac{X}{3} + \frac{4}{3} - 8 \cdot \frac{3}{3}$

Combine $- 8$ and $\frac{3}{3}$ .

$x = - \frac{X}{3} + \frac{4}{3} + \frac{- 8 \cdot 3}{3}$

Combine the numerators over the common denominator.

$x = - \frac{X}{3} + \frac{4 - 8 \cdot 3}{3}$

Simplify the numerator.

Multiply $- 8$ by $3$ .

$x = - \frac{X}{3} + \frac{4 - 24}{3}$

Subtract $24$ from $4$ .

$x = - \frac{X}{3} + \frac{- 20}{3}$

Move the negative in front of the fraction.

$x = - \frac{X}{3} - \frac{20}{3}$