Solve for x 32-(5+x)=20

$32 - (5 + x) = 20$

Simplify $32 - (5 + x)$ .

Simplify each term.

Apply the distributive property.

$32 - 1 \cdot 5 - x = 20$

Multiply $- 1$ by $5$ .

$32 - 5 - x = 20$

Subtract $5$ from $32$ .

$27 - x = 20$

Move all terms not containing $x$ to the right side of the equation.

Subtract $27$ from both sides of the equation.

$- x = 20 - 27$

Subtract $27$ from $20$ .

$- x = - 7$

Divide each term in $- x = - 7$ by $- 1$ and simplify.

Divide each term in $- x = - 7$ by $- 1$ .

$\frac{- x}{- 1} = \frac{- 7}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{x}{1} = \frac{- 7}{- 1}$

Divide $x$ by $1$ .

$x = \frac{- 7}{- 1}$

Simplify the right side.

Divide $- 7$ by $- 1$ .

$x = 7$