Solve for x 3e^(2x)-8=2e^x

$3 e^{2 x} - 8 = 2 e^{x}$

Step 1

Subtract $2 e^{x}$ from both sides of the equation.

$3 e^{2 x} - 8 - 2 e^{x} = 0$

Step 2

Rewrite $e^{2 x}$ as exponentiation.

$3 {(e^{x})}^{2} - 8 - 2 e^{x} = 0$

Step 3

Substitute $u$ for $e^{x}$ .

$3 u^{2} - 8 - 2 u = 0$

Step 4

Move $- 8$ .

$3 u^{2} - 2 u - 8 = 0$

Step 5

Solve for $u$ .

Factor by grouping.

For a polynomial of the form $a x^{2} + b x + c$ , rewrite the middle term as a sum of two terms whose product is $a \cdot c = 3 \cdot - 8 = - 24$ and whose sum is $b = - 2$ .

Factor $- 2$ out of $- 2 u$ .

$3 u^{2} - 2 u - 8 = 0$

Rewrite $- 2$ as $4$ plus $- 6$

$3 u^{2} + (4 - 6) u - 8 = 0$

Apply the distributive property.

$3 u^{2} + 4 u - 6 u - 8 = 0$

Factor out the greatest common factor from each group.

Group the first two terms and the last two terms.

$(3 u^{2} + 4 u) - 6 u - 8 = 0$

Factor out the greatest common factor (GCF) from each group.

$u (3 u + 4) - 2 (3 u + 4) = 0$

Factor the polynomial by factoring out the greatest common factor, $3 u + 4$ .

$(3 u + 4) (u - 2) = 0$

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$3 u + 4 = 0$

$u - 2 = 0$

Set $3 u + 4$ equal to $0$ and solve for $u$ .

Set $3 u + 4$ equal to $0$ .

$3 u + 4 = 0$

Solve $3 u + 4 = 0$ for $u$ .

Subtract $4$ from both sides of the equation.

$3 u = - 4$

Divide each term in $3 u = - 4$ by $3$ and simplify.

Divide each term in $3 u = - 4$ by $3$ .

$\frac{3 u}{3} = \frac{- 4}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 u}{3} = \frac{- 4}{3}$

Divide $u$ by $1$ .

$u = \frac{- 4}{3}$

Simplify the right side.

Move the negative in front of the fraction.

$u = - \frac{4}{3}$

Set $u - 2$ equal to $0$ and solve for $u$ .

Set $u - 2$ equal to $0$ .

$u - 2 = 0$

Add $2$ to both sides of the equation.

$u = 2$

The final solution is all the values that make $(3 u + 4) (u - 2) = 0$ true.

$u = - \frac{4}{3}, 2$

Step 6

Substitute $- \frac{4}{3}$ for $u$ in $u = e^{x}$ .

$- \frac{4}{3} = e^{x}$

Step 7

Solve $- \frac{4}{3} = e^{x}$ .

Rewrite the equation as $e^{x} = - \frac{4}{3}$ .

$e^{x} = - \frac{4}{3}$

Take the natural logarithm of both sides of the equation to remove the variable from the exponent.

$\ln (e^{x}) = \ln (- \frac{4}{3})$

The equation cannot be solved because $\ln (- \frac{4}{3})$ is undefined.

Undefined

There is no solution for $e^{x} = - \frac{4}{3}$

No solution

Step 8

Substitute $2$ for $u$ in $u = e^{x}$ .

$2 = e^{x}$

Step 9

Solve $2 = e^{x}$ .

Rewrite the equation as $e^{x} = 2$ .

$e^{x} = 2$

Take the natural logarithm of both sides of the equation to remove the variable from the exponent.

$\ln (e^{x}) = \ln (2)$

Expand the left side.

Expand $\ln (e^{x})$ by moving $x$ outside the logarithm.

$x \ln (e) = \ln (2)$

The natural logarithm of $e$ is $1$ .

$x \cdot 1 = \ln (2)$

Multiply $x$ by $1$ .

$x = \ln (2)$

Step 10

The result can be shown in multiple forms.

Exact Form:

$x = \ln (2)$

Decimal Form:

$x = 0.69314718 \dots$

Solve for x 3e^(2x)-8=2e^x

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