Solve for x (3x)/10+(7x)/5=17

$\frac{3 x}{10} + \frac{7 x}{5} = 17$

Step 1

Simplify $\frac{3 x}{10} + \frac{7 x}{5}$ .

To write $\frac{7 x}{5}$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$\frac{3 x}{10} + \frac{7 x}{5} \cdot \frac{2}{2} = 17$

Write each expression with a common denominator of $10$ , by multiplying each by an appropriate factor of $1$ .

Multiply $\frac{7 x}{5}$ by $\frac{2}{2}$ .

$\frac{3 x}{10} + \frac{7 x \cdot 2}{5 \cdot 2} = 17$

Multiply $5$ by $2$ .

$\frac{3 x}{10} + \frac{7 x \cdot 2}{10} = 17$

Combine the numerators over the common denominator.

$\frac{3 x + 7 x \cdot 2}{10} = 17$

Simplify the numerator.

Factor $x$ out of $3 x + 7 x \cdot 2$ .

Factor $x$ out of $3 x$ .

$\frac{x \cdot 3 + 7 x \cdot 2}{10} = 17$

Factor $x$ out of $7 x \cdot 2$ .

$\frac{x \cdot 3 + x (7 \cdot 2)}{10} = 17$

Factor $x$ out of $x \cdot 3 + x (7 \cdot 2)$ .

$\frac{x (3 + 7 \cdot 2)}{10} = 17$

Multiply $7$ by $2$ .

$\frac{x (3 + 14)}{10} = 17$

Add $3$ and $14$ .

$\frac{x \cdot 17}{10} = 17$

Move $17$ to the left of $x$ .

$\frac{17 x}{10} = 17$

Step 2

Multiply both sides of the equation by $\frac{10}{17}$ .

$\frac{10}{17} \cdot \frac{17 x}{10} = \frac{10}{17} \cdot 17$

Step 3

Simplify both sides of the equation.

Simplify the left side.

Simplify $\frac{10}{17} \cdot \frac{17 x}{10}$ .

Cancel the common factor of $10$ .

Cancel the common factor.

$\frac{10}{17} \cdot \frac{17 x}{10} = \frac{10}{17} \cdot 17$

Rewrite the expression.

$\frac{1}{17} (17 x) = \frac{10}{17} \cdot 17$

Cancel the common factor of $17$ .

Factor $17$ out of $17 x$ .

$\frac{1}{17} (17 (x)) = \frac{10}{17} \cdot 17$

Cancel the common factor.

$\frac{1}{17} (17 x) = \frac{10}{17} \cdot 17$

Rewrite the expression.

$x = \frac{10}{17} \cdot 17$

Simplify the right side.

Cancel the common factor of $17$ .

Cancel the common factor.

$x = \frac{10}{17} \cdot 17$

Rewrite the expression.

$x = 10$

Solve for x (3x)/10+(7x)/5=17

Related Questions

Support LCMGCF.com by disabling your adblocker.