Solve for x 3x+12-6x<=-9

$3 x + 12 - 6 x \leq - 9$

Step 1

Subtract $6 x$ from $3 x$ .

$- 3 x + 12 \leq - 9$

Step 2

Move all terms not containing $x$ to the right side of the inequality.

Subtract $12$ from both sides of the inequality.

$- 3 x \leq - 9 - 12$

Subtract $12$ from $- 9$ .

$- 3 x \leq - 21$

Step 3

Divide each term in $- 3 x \leq - 21$ by $- 3$ and simplify.

Divide each term in $- 3 x \leq - 21$ by $- 3$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- 3 x}{- 3} \geq \frac{- 21}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 x}{- 3} \geq \frac{- 21}{- 3}$

Divide $x$ by $1$ .

$x \geq \frac{- 21}{- 3}$

Simplify the right side.

Divide $- 21$ by $- 3$ .

$x \geq 7$

Step 4

The result can be shown in multiple forms.

Inequality Form:

$x \geq 7$

Interval Notation:

$[7, \infty)$

Solve for x 3x+12-6x<=-9

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