Solve for x 3x+15>=0

$3 x + 15 \geq 0$

Subtract $15$ from both sides of the inequality.

$3 x \geq - 15$

Divide each term in $3 x \geq - 15$ by $3$ and simplify.

Divide each term in $3 x \geq - 15$ by $3$ .

$\frac{3 x}{3} \geq \frac{- 15}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 x}{3} \geq \frac{- 15}{3}$

Divide $x$ by $1$ .

$x \geq \frac{- 15}{3}$

Simplify the right side.

Divide $- 15$ by $3$ .

$x \geq - 5$

The result can be shown in multiple forms.

Inequality Form:

$x \geq - 5$

Interval Notation:

$[- 5, \infty)$