Solve for x 3x-2-3(-1+2x)=2-2(x-1)

$3 x - 2 - 3 (- 1 + 2 x) = 2 - 2 (x - 1)$

Step 1

Simplify $3 x - 2 - 3 (- 1 + 2 x)$ .

Simplify each term.

Apply the distributive property.

$3 x - 2 - 3 \cdot - 1 - 3 (2 x) = 2 - 2 (x - 1)$

Multiply $- 3$ by $- 1$ .

$3 x - 2 + 3 - 3 (2 x) = 2 - 2 (x - 1)$

Multiply $2$ by $- 3$ .

$3 x - 2 + 3 - 6 x = 2 - 2 (x - 1)$

Simplify by adding terms.

Subtract $6 x$ from $3 x$ .

$- 3 x - 2 + 3 = 2 - 2 (x - 1)$

Add $- 2$ and $3$ .

$- 3 x + 1 = 2 - 2 (x - 1)$

Step 2

Simplify $2 - 2 (x - 1)$ .

Simplify each term.

Apply the distributive property.

$- 3 x + 1 = 2 - 2 x - 2 \cdot - 1$

Multiply $- 2$ by $- 1$ .

$- 3 x + 1 = 2 - 2 x + 2$

Add $2$ and $2$ .

$- 3 x + 1 = - 2 x + 4$

Step 3

Move all terms containing $x$ to the left side of the equation.

Add $2 x$ to both sides of the equation.

$- 3 x + 1 + 2 x = 4$

Add $- 3 x$ and $2 x$ .

$- x + 1 = 4$

Step 4

Move all terms not containing $x$ to the right side of the equation.

Subtract $1$ from both sides of the equation.

$- x = 4 - 1$

Subtract $1$ from $4$ .

$- x = 3$

Step 5

Divide each term in $- x = 3$ by $- 1$ and simplify.

Divide each term in $- x = 3$ by $- 1$ .

$\frac{- x}{- 1} = \frac{3}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{x}{1} = \frac{3}{- 1}$

Divide $x$ by $1$ .

$x = \frac{3}{- 1}$

Simplify the right side.

Divide $3$ by $- 1$ .

$x = - 3$

Solve for x 3x-2-3(-1+2x)=2-2(x-1)

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