Solve for x -(3x-2)=-4(x+1)-4

$- (3 x - 2) = - 4 (x + 1) - 4$

Step 1

Simplify $- (3 x - 2)$ .

Rewrite.

$0 + 0 - (3 x - 2) = - 4 (x + 1) - 4$

Simplify by adding zeros.

$- (3 x - 2) = - 4 (x + 1) - 4$

Apply the distributive property.

$- (3 x) - - 2 = - 4 (x + 1) - 4$

Multiply.

Multiply $3$ by $- 1$ .

$- 3 x - - 2 = - 4 (x + 1) - 4$

Multiply $- 1$ by $- 2$ .

$- 3 x + 2 = - 4 (x + 1) - 4$

Step 2

Simplify $- 4 (x + 1) - 4$ .

Simplify each term.

Apply the distributive property.

$- 3 x + 2 = - 4 x - 4 \cdot 1 - 4$

Multiply $- 4$ by $1$ .

$- 3 x + 2 = - 4 x - 4 - 4$

Subtract $4$ from $- 4$ .

$- 3 x + 2 = - 4 x - 8$

Step 3

Move all terms containing $x$ to the left side of the equation.

Add $4 x$ to both sides of the equation.

$- 3 x + 2 + 4 x = - 8$

Add $- 3 x$ and $4 x$ .

$x + 2 = - 8$

Step 4

Move all terms not containing $x$ to the right side of the equation.

Subtract $2$ from both sides of the equation.

$x = - 8 - 2$

Subtract $2$ from $- 8$ .

$x = - 10$