Solve for x 3x+2-(4x-1-9x)=6x-1

$3 x + 2 - (4 x - 1 - 9 x) = 6 x - 1$

Step 1

Simplify $3 x + 2 - (4 x - 1 - 9 x)$ .

Simplify each term.

Subtract $9 x$ from $4 x$ .

$3 x + 2 - (- 5 x - 1) = 6 x - 1$

Apply the distributive property.

$3 x + 2 - (- 5 x) - - 1 = 6 x - 1$

Multiply $- 5$ by $- 1$ .

$3 x + 2 + 5 x - - 1 = 6 x - 1$

Multiply $- 1$ by $- 1$ .

$3 x + 2 + 5 x + 1 = 6 x - 1$

Simplify by adding terms.

Add $3 x$ and $5 x$ .

$8 x + 2 + 1 = 6 x - 1$

Add $2$ and $1$ .

$8 x + 3 = 6 x - 1$

Step 2

Move all terms containing $x$ to the left side of the equation.

Subtract $6 x$ from both sides of the equation.

$8 x + 3 - 6 x = - 1$

Subtract $6 x$ from $8 x$ .

$2 x + 3 = - 1$

Step 3

Move all terms not containing $x$ to the right side of the equation.

Subtract $3$ from both sides of the equation.

$2 x = - 1 - 3$

Subtract $3$ from $- 1$ .

$2 x = - 4$

Step 4

Divide each term in $2 x = - 4$ by $2$ and simplify.

Divide each term in $2 x = - 4$ by $2$ .

$\frac{2 x}{2} = \frac{- 4}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{- 4}{2}$

Divide $x$ by $1$ .

$x = \frac{- 4}{2}$

Simplify the right side.

Divide $- 4$ by $2$ .

$x = - 2$