Solve for x 3x-20-7x=2x+20+2x

$3 x - 20 - 7 x = 2 x + 20 + 2 x$

Step 1

Subtract $7 x$ from $3 x$ .

$- 4 x - 20 = 2 x + 20 + 2 x$

Step 2

Add $2 x$ and $2 x$ .

$- 4 x - 20 = 4 x + 20$

Step 3

Move all terms containing $x$ to the left side of the equation.

Subtract $4 x$ from both sides of the equation.

$- 4 x - 20 - 4 x = 20$

Subtract $4 x$ from $- 4 x$ .

$- 8 x - 20 = 20$

Step 4

Move all terms not containing $x$ to the right side of the equation.

Add $20$ to both sides of the equation.

$- 8 x = 20 + 20$

Add $20$ and $20$ .

$- 8 x = 40$

Step 5

Divide each term in $- 8 x = 40$ by $- 8$ and simplify.

Divide each term in $- 8 x = 40$ by $- 8$ .

$\frac{- 8 x}{- 8} = \frac{40}{- 8}$

Simplify the left side.

Cancel the common factor of $- 8$ .

Cancel the common factor.

$\frac{- 8 x}{- 8} = \frac{40}{- 8}$

Divide $x$ by $1$ .

$x = \frac{40}{- 8}$

Simplify the right side.

Divide $40$ by $- 8$ .

$x = - 5$