Solve for x 3x-(2x-1)=7x-(3-5x)+(-x+24)

$3 x - (2 x - 1) = 7 x - (3 - 5 x) + (- x + 24)$

Since $x$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$7 x - (3 - 5 x) - x + 24 = 3 x - (2 x - 1)$

Simplify $7 x - (3 - 5 x) - x + 24$ .

Simplify each term.

Apply the distributive property.

$7 x - 1 \cdot 3 - (- 5 x) - x + 24 = 3 x - (2 x - 1)$

Multiply $- 1$ by $3$ .

$7 x - 3 - (- 5 x) - x + 24 = 3 x - (2 x - 1)$

Multiply $- 5$ by $- 1$ .

$7 x - 3 + 5 x - x + 24 = 3 x - (2 x - 1)$

Simplify by adding terms.

Add $7 x$ and $5 x$ .

$12 x - 3 - x + 24 = 3 x - (2 x - 1)$

Subtract $x$ from $12 x$ .

$11 x - 3 + 24 = 3 x - (2 x - 1)$

Add $- 3$ and $24$ .

$11 x + 21 = 3 x - (2 x - 1)$

Simplify $3 x - (2 x - 1)$ .

Simplify each term.

Apply the distributive property.

$11 x + 21 = 3 x - (2 x) - - 1$

Multiply $2$ by $- 1$ .

$11 x + 21 = 3 x - 2 x - - 1$

Multiply $- 1$ by $- 1$ .

$11 x + 21 = 3 x - 2 x + 1$

Subtract $2 x$ from $3 x$ .

$11 x + 21 = x + 1$

Move all terms containing $x$ to the left side of the equation.

Subtract $x$ from both sides of the equation.

$11 x + 21 - x = 1$

Subtract $x$ from $11 x$ .

$10 x + 21 = 1$

Move all terms not containing $x$ to the right side of the equation.

Subtract $21$ from both sides of the equation.

$10 x = 1 - 21$

Subtract $21$ from $1$ .

$10 x = - 20$

Divide each term in $10 x = - 20$ by $10$ and simplify.

Divide each term in $10 x = - 20$ by $10$ .

$\frac{10 x}{10} = \frac{- 20}{10}$

Simplify the left side.

Cancel the common factor of $10$ .

Cancel the common factor.

$\frac{10 x}{10} = \frac{- 20}{10}$

Divide $x$ by $1$ .

$x = \frac{- 20}{10}$

Simplify the right side.

Divide $- 20$ by $10$ .

$x = - 2$

Solve for x 3x-(2x-1)=7x-(3-5x)+(-x+24)

Related Questions

Support LCMGCF.com by disabling your adblocker.