Solve for x 3x+3y=4 and x-3y=1

$3 x + 3 y = 4$ and $x - 3 y = 1$

Step 1

The simplified system is the arbitrary solution of the original system of equations.

$y = \frac{4}{3} - x$

$y = - \frac{1}{3} + \frac{x}{3}$

Step 2

Simplify the right side.

Reorder $\frac{4}{3}$ and $- x$ .

$y = - x + \frac{4}{3}$

$y = - \frac{1}{3} + \frac{x}{3}$

$y = - x + \frac{4}{3}$

$y = - \frac{1}{3} + \frac{x}{3}$

Step 3

Simplify the right side.

Reorder $- \frac{1}{3}$ and $\frac{x}{3}$ .

$y = \frac{x}{3} - \frac{1}{3}$

$y = - x + \frac{4}{3}$

$y = \frac{x}{3} - \frac{1}{3}$

$y = - x + \frac{4}{3}$