Solve for x (3x-4b)+(7b+2x)=13b

$(3 x - 4 b) + (7 b + 2 x) = 13 b$

Step 1

Simplify $3 x - 4 b + 7 b + 2 x$ .

Add $3 x$ and $2 x$ .

$- 4 b + 7 b + 5 x = 13 b$

Add $- 4 b$ and $7 b$ .

$3 b + 5 x = 13 b$

Step 2

Move all terms not containing $x$ to the right side of the equation.

Subtract $3 b$ from both sides of the equation.

$5 x = 13 b - 3 b$

Subtract $3 b$ from $13 b$ .

$5 x = 10 b$

Step 3

Divide each term in $5 x = 10 b$ by $5$ and simplify.

Divide each term in $5 x = 10 b$ by $5$ .

$\frac{5 x}{5} = \frac{10 b}{5}$

Simplify the left side.

Cancel the common factor of $5$ .

Cancel the common factor.

$\frac{5 x}{5} = \frac{10 b}{5}$

Divide $x$ by $1$ .

$x = \frac{10 b}{5}$

Simplify the right side.

Cancel the common factor of $10$ and $5$ .

Factor $5$ out of $10 b$ .

$x = \frac{5 (2 b)}{5}$

Cancel the common factors.

Factor $5$ out of $5$ .

$x = \frac{5 (2 b)}{5 (1)}$

Cancel the common factor.

$x = \frac{5 (2 b)}{5 \cdot 1}$

Rewrite the expression.

$x = \frac{2 b}{1}$

Divide $2 b$ by $1$ .

$x = 2 b$