Solve for x 3x+4y>12

$3 x + 4 y > 12$

Step 1

Subtract $4 y$ from both sides of the inequality.

$3 x > 12 - 4 y$

Step 2

Divide each term in $3 x > 12 - 4 y$ by $3$ and simplify.

Divide each term in $3 x > 12 - 4 y$ by $3$ .

$\frac{3 x}{3} > \frac{12}{3} + \frac{- 4 y}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 x}{3} > \frac{12}{3} + \frac{- 4 y}{3}$

Divide $x$ by $1$ .

$x > \frac{12}{3} + \frac{- 4 y}{3}$

Simplify the right side.

Simplify each term.

Divide $12$ by $3$ .

$x > 4 + \frac{- 4 y}{3}$

Move the negative in front of the fraction.

$x > 4 - \frac{4 y}{3}$