Solve for x 3x-6+1=-2x-5+5x

$3 x - 6 + 1 = - 2 x - 5 + 5 x$

Since $x$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$- 2 x - 5 + 5 x = 3 x - 6 + 1$

Add $- 2 x$ and $5 x$ .

$3 x - 5 = 3 x - 6 + 1$

Add $- 6$ and $1$ .

$3 x - 5 = 3 x - 5$

Move all terms containing $x$ to the left side of the equation.

Subtract $3 x$ from both sides of the equation.

$3 x - 5 - 3 x = - 5$

Combine the opposite terms in $3 x - 5 - 3 x$ .

Subtract $3 x$ from $3 x$ .

$0 - 5 = - 5$

Subtract $5$ from $0$ .

$- 5 = - 5$

Since $- 5 = - 5$ , the equation will always be true for any value of $x$ .

All real numbers

The result can be shown in multiple forms.

All real numbers

Interval Notation:

$(- \infty, \infty)$