Solve for x (3x)/6+1=7

$\frac{3 x}{6} + 1 = 7$

Step 1

Cancel the common factor of $3$ and $6$ .

Factor $3$ out of $3 x$ .

$\frac{3 (x)}{6} + 1 = 7$

Cancel the common factors.

Factor $3$ out of $6$ .

$\frac{3 x}{3 \cdot 2} + 1 = 7$

Cancel the common factor.

$\frac{3 x}{3 \cdot 2} + 1 = 7$

Rewrite the expression.

$\frac{x}{2} + 1 = 7$

Step 2

Move all terms not containing $x$ to the right side of the equation.

Subtract $1$ from both sides of the equation.

$\frac{x}{2} = 7 - 1$

Subtract $1$ from $7$ .

$\frac{x}{2} = 6$

Step 3

Multiply both sides of the equation by $2$ .

$2 \frac{x}{2} = 2 \cdot 6$

Step 4

Simplify both sides of the equation.

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$2 \frac{x}{2} = 2 \cdot 6$

Rewrite the expression.

$x = 2 \cdot 6$

Simplify the right side.

Multiply $2$ by $6$ .

$x = 12$