Solve for x 3x+6=3(x+2)

$3 x + 6 = 3 (x + 2)$

Simplify $3 (x + 2)$ .

Rewrite.

$3 x + 6 = 0 + 0 + 3 (x + 2)$

Simplify by adding zeros.

$3 x + 6 = 3 (x + 2)$

Apply the distributive property.

$3 x + 6 = 3 x + 3 \cdot 2$

Multiply $3$ by $2$ .

$3 x + 6 = 3 x + 6$

Move all terms containing $x$ to the left side of the equation.

Subtract $3 x$ from both sides of the equation.

$3 x + 6 - 3 x = 6$

Combine the opposite terms in $3 x + 6 - 3 x$ .

Subtract $3 x$ from $3 x$ .

$0 + 6 = 6$

Add $0$ and $6$ .

$6 = 6$

Since $6 = 6$ , the equation will always be true for any value of $x$ .

All real numbers

The result can be shown in multiple forms.

All real numbers

Interval Notation:

$(- \infty, \infty)$