Solve for x 3x+6y=12

$3 x + 6 y = 12$

Step 1

Subtract $6 y$ from both sides of the equation.

$3 x = 12 - 6 y$

Step 2

Divide each term in $3 x = 12 - 6 y$ by $3$ and simplify.

Divide each term in $3 x = 12 - 6 y$ by $3$ .

$\frac{3 x}{3} = \frac{12}{3} + \frac{- 6 y}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 x}{3} = \frac{12}{3} + \frac{- 6 y}{3}$

Divide $x$ by $1$ .

$x = \frac{12}{3} + \frac{- 6 y}{3}$

$x = \frac{12}{3} + \frac{- 6 y}{3}$

$x = \frac{12}{3} + \frac{- 6 y}{3}$

Simplify the right side.

Simplify each term.

Divide $12$ by $3$ .

$x = 4 + \frac{- 6 y}{3}$

Cancel the common factor of $- 6$ and $3$ .

Factor $3$ out of $- 6 y$ .

$x = 4 + \frac{3 (- 2 y)}{3}$

Cancel the common factors.

Factor $3$ out of $3$ .

$x = 4 + \frac{3 (- 2 y)}{3 (1)}$

Cancel the common factor.

$x = 4 + \frac{3 (- 2 y)}{3 \cdot 1}$

Rewrite the expression.

$x = 4 + \frac{- 2 y}{1}$

Divide $- 2 y$ by $1$ .

$x = 4 - 2 y$

$x = 4 - 2 y$

$x = 4 - 2 y$

$x = 4 - 2 y$

$x = 4 - 2 y$

$x = 4 - 2 y$

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