Solve for x 3x-8(2x+3)=-6(2x+5)

$3 x - 8 (2 x + 3) = - 6 (2 x + 5)$

Simplify $3 x - 8 (2 x + 3)$ .

Simplify each term.

Apply the distributive property.

$3 x - 8 (2 x) - 8 \cdot 3 = - 6 (2 x + 5)$

Multiply $2$ by $- 8$ .

$3 x - 16 x - 8 \cdot 3 = - 6 (2 x + 5)$

Multiply $- 8$ by $3$ .

$3 x - 16 x - 24 = - 6 (2 x + 5)$

Subtract $16 x$ from $3 x$ .

$- 13 x - 24 = - 6 (2 x + 5)$

Simplify $- 6 (2 x + 5)$ .

Apply the distributive property.

$- 13 x - 24 = - 6 (2 x) - 6 \cdot 5$

Multiply.

Multiply $2$ by $- 6$ .

$- 13 x - 24 = - 12 x - 6 \cdot 5$

Multiply $- 6$ by $5$ .

$- 13 x - 24 = - 12 x - 30$

Move all terms containing $x$ to the left side of the equation.

Add $12 x$ to both sides of the equation.

$- 13 x - 24 + 12 x = - 30$

Add $- 13 x$ and $12 x$ .

$- x - 24 = - 30$

Move all terms not containing $x$ to the right side of the equation.

Add $24$ to both sides of the equation.

$- x = - 30 + 24$

Add $- 30$ and $24$ .

$- x = - 6$

Divide each term in $- x = - 6$ by $- 1$ and simplify.

Divide each term in $- x = - 6$ by $- 1$ .

$\frac{- x}{- 1} = \frac{- 6}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{x}{1} = \frac{- 6}{- 1}$

Divide $x$ by $1$ .

$x = \frac{- 6}{- 1}$

Simplify the right side.

Divide $- 6$ by $- 1$ .

$x = 6$