Solve for x 3x-8=(8x+4)/2

$3 x - 8 = \frac{8 x + 4}{2}$

Cancel the common factor of $8 x + 4$ and $2$ .

Factor $2$ out of $8 x$ .

$3 x - 8 = \frac{2 (4 x) + 4}{2}$

Factor $2$ out of $4$ .

$3 x - 8 = \frac{2 (4 x) + 2 \cdot 2}{2}$

Factor $2$ out of $2 (4 x) + 2 (2)$ .

$3 x - 8 = \frac{2 (4 x + 2)}{2}$

Cancel the common factors.

Factor $2$ out of $2$ .

$3 x - 8 = \frac{2 (4 x + 2)}{2 (1)}$

Cancel the common factor.

$3 x - 8 = \frac{2 (4 x + 2)}{2 \cdot 1}$

Rewrite the expression.

$3 x - 8 = \frac{4 x + 2}{1}$

Divide $4 x + 2$ by $1$ .

$3 x - 8 = 4 x + 2$

Solve for $x$ .

Move all terms containing $x$ to the left side of the equation.

Subtract $4 x$ from both sides of the equation.

$3 x - 8 - 4 x = 2$

Subtract $4 x$ from $3 x$ .

$- x - 8 = 2$

Move all terms not containing $x$ to the right side of the equation.

Add $8$ to both sides of the equation.

$- x = 2 + 8$

Add $2$ and $8$ .

$- x = 10$

Divide each term in $- x = 10$ by $- 1$ and simplify.

Divide each term in $- x = 10$ by $- 1$ .

$\frac{- x}{- 1} = \frac{10}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{x}{1} = \frac{10}{- 1}$

Divide $x$ by $1$ .

$x = \frac{10}{- 1}$

Simplify the right side.

Divide $10$ by $- 1$ .

$x = - 10$