Solve for x 3x+9<0

$3 x + 9 < 0$

Step 1

Subtract $9$ from both sides of the inequality.

$3 x < - 9$

Step 2

Divide each term in $3 x < - 9$ by $3$ and simplify.

Divide each term in $3 x < - 9$ by $3$ .

$\frac{3 x}{3} < \frac{- 9}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 x}{3} < \frac{- 9}{3}$

Divide $x$ by $1$ .

$x < \frac{- 9}{3}$

Simplify the right side.

Divide $- 9$ by $3$ .

$x < - 3$

Step 3

The result can be shown in multiple forms.

Inequality Form:

$x < - 3$

Interval Notation:

$(- \infty, - 3)$