Solve for x 3x+x+x+x-3-2=7+x+x

$3 x + x + x + x - 3 - 2 = 7 + x + x$

Simplify $3 x + x + x + x - 3 - 2$ .

Add $3 x$ and $x$ .

$4 x + x + x - 3 - 2 = 7 + x + x$

Add $4 x$ and $x$ .

$5 x + x - 3 - 2 = 7 + x + x$

Add $5 x$ and $x$ .

$6 x - 3 - 2 = 7 + x + x$

Subtract $2$ from $- 3$ .

$6 x - 5 = 7 + x + x$

Add $x$ and $x$ .

$6 x - 5 = 7 + 2 x$

Move all terms containing $x$ to the left side of the equation.

Subtract $2 x$ from both sides of the equation.

$6 x - 5 - 2 x = 7$

Subtract $2 x$ from $6 x$ .

$4 x - 5 = 7$

Move all terms not containing $x$ to the right side of the equation.

Add $5$ to both sides of the equation.

$4 x = 7 + 5$

Add $7$ and $5$ .

$4 x = 12$

Divide each term in $4 x = 12$ by $4$ and simplify.

Divide each term in $4 x = 12$ by $4$ .

$\frac{4 x}{4} = \frac{12}{4}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 x}{4} = \frac{12}{4}$

Divide $x$ by $1$ .

$x = \frac{12}{4}$

Simplify the right side.

Divide $12$ by $4$ .

$x = 3$