Solve for x 3x+y=12

$3 x + y = 12$

Step 1

Subtract $y$ from both sides of the equation.

$3 x = 12 - y$

Step 2

Divide each term in $3 x = 12 - y$ by $3$ and simplify.

Divide each term in $3 x = 12 - y$ by $3$ .

$\frac{3 x}{3} = \frac{12}{3} + \frac{- y}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 x}{3} = \frac{12}{3} + \frac{- y}{3}$

Divide $x$ by $1$ .

$x = \frac{12}{3} + \frac{- y}{3}$

Simplify the right side.

Simplify each term.

Divide $12$ by $3$ .

$x = 4 + \frac{- y}{3}$

Move the negative in front of the fraction.

$x = 4 - \frac{y}{3}$