Solve for x 3x-y<3

$3 x - y < 3$

Step 1

Add $y$ to both sides of the inequality.

$3 x < 3 + y$

Step 2

Divide each term in $3 x < 3 + y$ by $3$ and simplify.

Divide each term in $3 x < 3 + y$ by $3$ .

$\frac{3 x}{3} < \frac{3}{3} + \frac{y}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 x}{3} < \frac{3}{3} + \frac{y}{3}$

Divide $x$ by $1$ .

$x < \frac{3}{3} + \frac{y}{3}$

Simplify the right side.

Divide $3$ by $3$ .

$x < 1 + \frac{y}{3}$