Solve for x 3x+y+4-(y+6)=14+x

$3 x + y + 4 - (y + 6) = 14 + x$

Simplify $3 x + y + 4 - (y + 6)$ .

Simplify each term.

Apply the distributive property.

$3 x + y + 4 - y - 1 \cdot 6 = 14 + x$

Multiply $- 1$ by $6$ .

$3 x + y + 4 - y - 6 = 14 + x$

Simplify by adding terms.

Combine the opposite terms in $3 x + y + 4 - y - 6$ .

Subtract $y$ from $y$ .

$3 x + 0 + 4 - 6 = 14 + x$

Add $3 x$ and $0$ .

$3 x + 4 - 6 = 14 + x$

Subtract $6$ from $4$ .

$3 x - 2 = 14 + x$

Move all terms containing $x$ to the left side of the equation.

Subtract $x$ from both sides of the equation.

$3 x - 2 - x = 14$

Subtract $x$ from $3 x$ .

$2 x - 2 = 14$

Move all terms not containing $x$ to the right side of the equation.

Add $2$ to both sides of the equation.

$2 x = 14 + 2$

Add $14$ and $2$ .

$2 x = 16$

Divide each term in $2 x = 16$ by $2$ and simplify.

Divide each term in $2 x = 16$ by $2$ .

$\frac{2 x}{2} = \frac{16}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{16}{2}$

Divide $x$ by $1$ .

$x = \frac{16}{2}$

Simplify the right side.

Divide $16$ by $2$ .

$x = 8$